Memorable moment r celebrated together,
Here is a wishing that
the coming year is a glorious one
that rewards all your
future endeavors with success.
Happy New Year
I designed this blog to help and get benefited by their deeds in my career.I hope you all utilise this opportunity and get benefited. ****Feel free to contact me ***** I will soon update remaining........ keep visiting ........
Friday, December 31, 2010
Wednesday, December 29, 2010
Results 4-1 JNTU - K
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Monday, December 6, 2010
ANSWERS For Questions directions-for-questions-from-1-to-2
Answer for question 1 & 2 :-
⇒r = 3.5 (sqrt(2))
⇒ 2r = 7 sqrt(2) , side of the smallest square.
Diagonal of the innermost square = 14 units.
Diagonal of the largest square will be 14+ [(1.5) × 2] × 4
= 14 + 12 = 26 units
⇒ Area of the largest square
= 0.5 × (diagonal)2 = 338 sq units and area of the smallest square = (7 sqrt(2) )2 sq. units.
Required difference = 338 – 98 = 240 square units.
Let p be the number of problems on the test.
student was six and there were six questions total on the test. Hence, option (2) is the correct choice
Let n be the number of problems solved by the tenth student.
Then n <= p.
The number of problems solved, counted with multiplicity, is 7p
since each student solved seven questions.
However, we also know that the first nine students solved four questions each and the tenth solved n questions,
so
7p = (4×9) +n.
Re-arranging gives us
p = (36 + n)/7
Recalling that n <= p, we have
n <= p ⇒ 7n <= 7p ⇒ 7n <= 36 + n ⇒ 6n <= 36 ⇒ n <= 6.
Therefore, we are looking for non-negative n such that p = (36 + n)/7 and n <= 6
Therefore n = 6 and so p = 6. That is, the number of problems solved by the tenth
n <= p ⇒ 7n <= 7p ⇒ 7n <= 36 + n ⇒ 6n <= 36 ⇒ n <= 6.
Therefore, we are looking for non-negative n such that p = (36 + n)/7 and n <= 6
Therefore n = 6 and so p = 6. That is, the number of problems solved by the tenth
student was six and there were six questions total on the test. Hence, option (2) is the correct choice
3.) Given
(xy)z = 64
since positive integral
Whenz = 1, xy = 64. The total number of factors of 64 is 7.
z = 2, xy = 8. The total number of factors of 8 is 4.
z = 3, xy = 4. The total number of factors of 4 is 3.
z = 6, xy = 2. the total number of factors of 2 is 2
Hence, total number of positive integral solutions is 16.
z = 2, xy = 8. The total number of factors of 8 is 4.
z = 3, xy = 4. The total number of factors of 4 is 3.
z = 6, xy = 2. the total number of factors of 2 is 2
Hence, total number of positive integral solutions is 16.
4.) Diameter of the circle is equal to the side of the smallest
square is πr2 = 77⇒r = 3.5 (sqrt(2))
⇒ 2r = 7 sqrt(2) , side of the smallest square.
Diagonal of the innermost square = 14 units.
Diagonal of the largest square will be 14+ [(1.5) × 2] × 4
= 14 + 12 = 26 units
⇒ Area of the largest square
= 0.5 × (diagonal)2 = 338 sq units and area of the smallest square = (7 sqrt(2) )2 sq. units.
Required difference = 338 – 98 = 240 square units.
5 .) Total number of ways of dividing 24 boys in two distinct sub-sections is 24C12 = 24!/(12! 12!)
There can be two ways in which two shortest boys lie in different sub-section and correspondingly the remaining 22 boys can be divided into two distinct sub-sections in 22C11 ways.
∴ Probability = (2 x 22C11 )/24C12 = 12/23
6.)
7 ) here are 18 possible values of x and 9 possible values of y.
Since, BC is parallel to the X – axis, therefore AB will be parallel to the Y – axis.
The X – coordinate of points B and A will be same and the Y – coordinate of points B and C will be same.
For, every chosen co – ordinate of point B, the Y – coordinate of point A can be chosen in
9 – 1 = 8 ways and the X – coordinate of point A can be chosen in 18 – 1 = 17 ways.
Number of ways in which co – ordinate of point B can be chosen = 18 x 9
Total number of distinct triangles = 18 x 9 x 17 x 8 = 22032
8 .) Question
There can be two ways in which two shortest boys lie in different sub-section and correspondingly the remaining 22 boys can be divided into two distinct sub-sections in 22C11 ways.
∴ Probability = (2 x 22C11 )/24C12 = 12/23
6.)
7 ) here are 18 possible values of x and 9 possible values of y.
Since, BC is parallel to the X – axis, therefore AB will be parallel to the Y – axis.
The X – coordinate of points B and A will be same and the Y – coordinate of points B and C will be same.
For, every chosen co – ordinate of point B, the Y – coordinate of point A can be chosen in
9 – 1 = 8 ways and the X – coordinate of point A can be chosen in 18 – 1 = 17 ways.
Number of ways in which co – ordinate of point B can be chosen = 18 x 9
Total number of distinct triangles = 18 x 9 x 17 x 8 = 22032
8 .) Question
The maximum possible area (in square units) of such a triangle ABC is ?
For maximum possible area of such a triangle ABC, the co – ordinates of point B, A and C should be
(- 8, 9), (- 8, 17) and (17, 9) respectively.
Maximum Area = (1/2) x 25 x 8 = 100 square units.
9 .)
10 ) Let, the average age of the family when the first child was born be 'x' years.
Therefore, the total age of the family when the first child was born is 3x.
Let, after a years, the second child was born:
Therefore, (3x + 3a) = 18 x 4 = 72
Let, after another b years, the third child was born
Therefore, 72 + 4b = 16 x 5
b = 2,
Let, after another c years, the fourth child was born
Therefore, 80 + 5c = 20 x 6 = 120
c = 8
Let, after another d years, the fifth child was born
Therefore, 120 + 6d = 24 x 7 = 168
d = 8.
Let, after another 'e' years the average age of the family is 28 years.
Also, 168 + 7e = 28 x 8 = 224
7e = 56
e = 8
Also, a + b + c + d + e = Present age of the eldest child = 27
a = 27 – 26 = 1 year.
3x + 3 = 72
x = 23.
(- 8, 9), (- 8, 17) and (17, 9) respectively.
Maximum Area = (1/2) x 25 x 8 = 100 square units.
9 .)
10 ) Let, the average age of the family when the first child was born be 'x' years.
Therefore, the total age of the family when the first child was born is 3x.
Let, after a years, the second child was born:
Therefore, (3x + 3a) = 18 x 4 = 72
Let, after another b years, the third child was born
Therefore, 72 + 4b = 16 x 5
b = 2,
Let, after another c years, the fourth child was born
Therefore, 80 + 5c = 20 x 6 = 120
c = 8
Let, after another d years, the fifth child was born
Therefore, 120 + 6d = 24 x 7 = 168
d = 8.
Let, after another 'e' years the average age of the family is 28 years.
Also, 168 + 7e = 28 x 8 = 224
7e = 56
e = 8
Also, a + b + c + d + e = Present age of the eldest child = 27
a = 27 – 26 = 1 year.
3x + 3 = 72
x = 23.
I AM EXTREMELY SORRY FOR DELAY IN ANSWERS
- Hide quoted text -
Points to remember while preparing for GATE 2011
Points to remember while preparing for GATE 2011
Systematic preparation is only the way to qualify the GATE 2011 and all public sector exams. Following these suggestion for success in GATE and public sector exams.
1. Bring previous year GATE exam question papers (gate exam questions are available very easily in the market).
2. Start back study (i.e. pick up GATE questions and find the solution) I personally believe if you practice to solve all the gate questions from the previous asked (at least 6-8 year) you can definitely qualify the gate exam.
3. Another important fact is: do not answer wrong during the gate examination even your total score is only 35 to 45 % (mostly people could not qualify gate exam because they attempt to answer wrong question).
4. Keep in mind, most of the time negative marking is only responsible to the failure.
5. Join some Gate exam discussion and online sharing forum and discuss your doubts and get touch with Gate Aspirants.
I hope if you follow all these suggestion you will definitely qualify GATE exam.
1. Bring previous year GATE exam question papers (gate exam questions are available very easily in the market).
2. Start back study (i.e. pick up GATE questions and find the solution) I personally believe if you practice to solve all the gate questions from the previous asked (at least 6-8 year) you can definitely qualify the gate exam.
3. Another important fact is: do not answer wrong during the gate examination even your total score is only 35 to 45 % (mostly people could not qualify gate exam because they attempt to answer wrong question).
4. Keep in mind, most of the time negative marking is only responsible to the failure.
5. Join some Gate exam discussion and online sharing forum and discuss your doubts and get touch with Gate Aspirants.
I hope if you follow all these suggestion you will definitely qualify GATE exam.
Preparing for GATE 2011 can be made easy in 10 steps
Preparing for GATE can be as easy as preparing for your college examinations. Just take little cautions while studying any topic and do remember that GATE paper focus on your in depth knowledge of subject, your basics, presence of mind during examination etc.
1. Always follow standard books for GATE. Try to cover complete syllabus. If not possible expertise in what ever portion of syllabus you practice.
2. Try preparing notes after reading every chapter topic. This may initially take some time but will help you while revising before paper.
3. While reading any chapter topic does ask your self following questions What, How, and why and see improvement.
4. Best way to prepare is to follow cycle Learn, Test, Analyze, Improve, Learn, Test, Analyze, and Improve.
5. Do remember that GATE is completely objective question based test. Most of time solving objective questions is tricky. Learn tips to solve GATE objective questions.
7. In case of doubts do ask some expert or use forums to discuss questions as provided by httpwww.indiastudychannel.com or ask me.
8. Don’t worry if your percentage in university exams is low as GATE admissions do not consider them. Just maintain minimum percentage required by many colleges including IIT’s. Look at GATE Cutoff and eligibility section to know eligibility and cut off of various colleges.
9. Group study is one of the best ways of preparation. Divide sections topics between you and your partner and have a brief session on topic from your friend before you actually start topic. This will save your time and efforts and will improve your and your partner’s understanding on the topic.
10. Normally coaching GATE is not required but if you are not able to concentrate much then this is a good option.
GATE – 2011 Preparation Tips
GATE – 2011 Preparation Tips
1. Material Collection - Syllabus
- All the relevant books based on the subject(Divide the books in two groups - (1)Fundamental and basic concepts (2)Problem oriented
- Some books helpful for pre-requisite knowledge on the subject
- Some good guide books for GATE
- Previous questions papers
2. Keep contact with some expert and GATE experienced persons
3. Study - Syllabus and Previous questions papers 4. Start from the first chapter
- Read at least 5 books, it will widen your knowledge(if necessary consult with the books for pre-requisite knowledge or with some expert)
- Note down the probable concepts (definitions, unit, dimension etc.)
- Note down necessary theories, formulae etc
- Solve problems as maximum as possible(from text books, Guide books etc)
- Think about various tricks in solving problems(if necessary, note it)
- Go for series of self tests based on this chapter(take other's help to conduct tests)
- Continue the self tests until getting a very good score
5. Solve more and more problems, discover more and more new tricks…
6. Follow the same procedure for the rest chapters 7. Finally, go for self tests based on whole syllabus(take other's help to conduct these tests)
8. On the exam day…you will be at the Pick, who can stop you?
Wednesday, December 1, 2010
Question 1.
(linear equations)
What is the number of problems solved by the tenth student? Correct Answer: 2 6 4 7 3 Skip this question |
Question 2.
(linear equations)
What is the number of problems on the test? Correct Answer: 2 5 6 4 7 3 Skip this question |
Question 3.
Find the number of positive integral solutions of the equation (xy)z = 64. Correct Answer: 3 14 15 16 17 18 Skip this question |
Question 4.
5 concentric squares each having different area are drawn on a sheet of paper. If the area of the circle inscribed in the smallest square is 77 square units and the distance between the corresponding vertices of consecutive squares is 1.5 units, then find the difference between the areas of the largest and the smallest square in square units. (Take pie = 22/7) Correct Answer: 1 240 264 224 216 256 Skip this question |
Question 5.
A class of 24 boys was divided into two sub-sections containing 12 boys each. What is the probability that the two shortest boys of the class are in different sub-sections, if all boys have different heights? Correct Answer: 3 7/24 6/23 12/23 14/23 None of these Skip this question |
Question 6.
Two wheels of diameters 7 cm and 14 cm start rolling simultaneously towards each other from two points which are 1990.5 cm apart. Both wheels make the same number of revolutions per second. If both the wheels meet (touch externally) after 10 seconds, then what is the speed of the smaller wheel? Correct Answer: 2 132 cm/sec 66 cm/sec 44 cm/sec 22 cm/sec 67 cm/sec Skip this question |
Question 7.
(permutaion and combination)
How many distinct triangles ABC are possible? Correct Answer: 2 24000 22032 18724 27564 Infinitely Many Skip this question |
Question 8.
(permutaion and combination)
The maximum possible area (in square units) of such a triangle ABC is Correct Answer: 2 84 100 104 120 92 Skip this question |
Question 9.
‘S’ denotes the sum to infinity and ‘Sn’ denotes the sum to ‘n’ terms of the series 1 + 4/5 + 16/25 + ...+ If S - Sn < 5/2. then the least value of ‘n’ is Correct Answer: 3 2 3 4 5 6 Skip this question |
Question 10.
(linear equations)
What is the difference between the age of the first and the second child Correct Answer: 3 3 years 2 years 1 year 5 years Cannot be determined. Skip this question |
For the students: online test
For the students: online test: "check your basic knowledge on electronics : ATTENTION: A browser version of 4.0 or higher or Explorer must be used otherwise th..."
Friday, November 26, 2010
check once
check your basic knowledge on electronics :
R U Electronics students ? then Y waiting come and check out yours stuff .....
visit: http://ece-08.blogspot.com/p/attention-browser-version-of-4.html
R U Electronics students ? then Y waiting come and check out yours stuff .....
visit: http://ece-08.blogspot.com/p/attention-browser-version-of-4.html
Wednesday, November 24, 2010
academics
ACADEMIC CALENDAR FOR THE COMMENCEMENT OF CLASS WORK
FOR B.TECH/B.PHARM II, III & IV YEAR-II SEMESTER
The Proposed Academic Calendar for B.Tech/B.Pharm II, III & IV Year-II Semester Regular During the year 2010-11 is detailed below.
B.TECH/B.PHARM II, III & IV YEAR-II SEMESTER | |||
Description | From | To | Weeks |
Commencement of Class Work | 29-11-2010 | - | - |
I Unit of Instructions | 29-11-2010 | 22-01-2011 | 8W |
I Mid Examinations | 24-01-2011 | 29-01-2011 | 1W |
II Unit of Instruction | 31-01-2011 | 26-03-2011 | 8W |
II Mid Examination | 28-03-2011 | 2-04-2011 | 1W |
Preparation & Practicals | 4-04-2011 | 16-04-2011 | 2W |
End Examinations | 18-04-2011 | 30-04-2011 | 2W |
NEXT ACADEMIC YEAR CLASS WORK:13-06-2011
quiz
http://ece-08.blogspot.com/p/puzzles-and-quizzes.html
Hi friends here i am glad to propose a new page in blog named "Puzzles And Quizzes" to develop the analytical skills and aptitude skills...
Here i would like to give weekly puzzles and quiz questions. Answer to the puzzles are sent the blogs email id : blogece08@gmail.com
correct answer with appropriate solutions will be sent back.....
Hi friends here i am glad to propose a new page in blog named "Puzzles And Quizzes" to develop the analytical skills and aptitude skills...
Here i would like to give weekly puzzles and quiz questions. Answer to the puzzles are sent the blogs email id : blogece08@gmail.com
correct answer with appropriate solutions will be sent back.....
Monday, November 22, 2010
Books for ECE gate
It is time to prepare for gate who are appearing for gate 2011 and 2012. it is well known to all that February 13th(second sunday) is exam. some important text books for ECE
**** The reference books for GATE ECE students are below.
**** The reference books for GATE ECE students are below.
Linear Algebra, Numerical Methods,Transform Theory
Higher Engineering Mathematics by B.S.Grewal
Higher Engineering Mathematics by B.S.Grewal
Calculus, Differential equations, Complex variables:
Intermediate Mathematics, S.chand publications by B.V.Sastry , K.Venkateswarlu ( if i remember ) both the volumes.
Intermediate Mathematics, S.chand publications by B.V.Sastry , K.Venkateswarlu ( if i remember ) both the volumes.
Probability and Statistics:
Probability , statistics and queuing theory by S.C.Gupta & V.K.Kapoor
Probability , statistics and queuing theory by S.C.Gupta & V.K.Kapoor
Networks: Network graphs:
Network Analysis by Van Valkenburg
Network Theory by Alexander Sadiku, UA Bakshi
Network Theory by Shaum’s outline, Robbins and Miller
Network Analysis by Van Valkenburg
Network Theory by Alexander Sadiku, UA Bakshi
Network Theory by Shaum’s outline, Robbins and Miller
Electronic Devices
Electronic Devices and Circuits by Boylestead
Solid State Electronic Devices by Benjamin G Streetman
Integrated electronics by Milman Halkias
Electronic Devices and Circuits by David A Bell
Integrated Circuits: Sedra Smith, K.R. Botkar
Electronic Principals by Malvino
Electronic Devices and Circuits by Boylestead
Solid State Electronic Devices by Benjamin G Streetman
Integrated electronics by Milman Halkias
Electronic Devices and Circuits by David A Bell
Integrated Circuits: Sedra Smith, K.R. Botkar
Electronic Principals by Malvino
Analog and Digital Circuits
Engineering Circuit Analysis Hayt & Kemmerly
Electric Circuits by Joseph A. Edminister
Fundamentals of Electric Circuits – Sadiku
Electronic Circuit Analysis by Donald Neamen
Electronic Devices and Circuits by Boylestead
Micro Electronic Circuits by Sedra & Smith
Digital Circuits Anand Kumar, Morris Mano
Engineering Circuit Analysis Hayt & Kemmerly
Electric Circuits by Joseph A. Edminister
Fundamentals of Electric Circuits – Sadiku
Electronic Circuit Analysis by Donald Neamen
Electronic Devices and Circuits by Boylestead
Micro Electronic Circuits by Sedra & Smith
Digital Circuits Anand Kumar, Morris Mano
Signals and Systems:
Signals and System by Oppenham and Schiener
Signals and System: by Schaum Series, Willsky & Nacob
Signals and System by Sanjay Sharma
Signals and System by Oppenham and Schiener
Signals and System: by Schaum Series, Willsky & Nacob
Signals and System by Sanjay Sharma
Control Systems:
Control Systems by Ogatta,Kuo
Linear Control Systems by B.S Manke.
Control Systems by Ogatta,Kuo
Linear Control Systems by B.S Manke.
Communications:
Communication Systems by Simon Haykin
Principle of Communication System by B. P. Lathi
Principle of Communication System by Taub & Schilling
Communication Systems by Carlson
Communication Systems by Sanjay Sharma
Communication Systems by Simon Haykin
Principle of Communication System by B. P. Lathi
Principle of Communication System by Taub & Schilling
Communication Systems by Carlson
Communication Systems by Sanjay Sharma
Electromagnetics
Electromagnetic Waves & Radiating Systems by Hayt, JD Kraus
Elements of Electromagneticsby Sadiku
Electromagnetics by J.D.Kraus
Engineering Applications of Electromagnetic Theory by Liao
Electromagnetic Waves & Radiating Systems by Hayt, JD Kraus
Elements of Electromagneticsby Sadiku
Electromagnetics by J.D.Kraus
Engineering Applications of Electromagnetic Theory by Liao
Few other useful books for GATE ECE preparation.
Gate 2010 by R.S. Kanodia (for questions only)
Previous GATE Question papers(Made Easy Publishers,GK publishers etc)
Previous Engg Services question papers(Made Easy Publishers)
Aptitude Test-D R Choudhary
GATE Physics Self Study Book by Surekha Tomar
Multiple Choice Questions with Explainatory Answers by UPKAR Publication , Agra
Gate 2010 by R.S. Kanodia (for questions only)
Previous GATE Question papers(Made Easy Publishers,GK publishers etc)
Previous Engg Services question papers(Made Easy Publishers)
Aptitude Test-D R Choudhary
GATE Physics Self Study Book by Surekha Tomar
Multiple Choice Questions with Explainatory Answers by UPKAR Publication , Agra
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Saturday, October 30, 2010
ELIGIBILITY FOR IIT JEE 2011
ELIGIBILITY FOR IIT JEE 2011
Eligibility: You must make sure that you satisfy all the eligibility conditions given below for appearing in JEE-2011
Date of birth: Candidate belonging to GE, OBC and DS categories must be born on or after October 01, 1986 and those belonging to SC, ST and PD categories must be born on or after October 01, 1981
Year of passing qualifying examination (QE): Must have passed the qualifying examination, namely, XII standard or any equivalent examination, after 1st October 2009 or in the year 2010 or will be appearing in 2011
Minimum percentage of marks in QE: candidates belonging to GE, OBC and DS categories must secure at least 60% marks and candidates belonging to SC, ST and PD categories must secure at least 55% marks in aggregate in the qualifying examination
Important notes: (i) You can attempt JEE only twice, in consecutive years. That means you should have attempted JEE for the first time in 2010 or will be appearing in 2011
(ii) If you have accepted admission after qualifying in JEE in earlier years by paying full fees at any of the IITs, IT-BHU, Varanasi or ISM, Dhanbad, you will not be eligible to write JEE at all, irrespective of whether or not you joined in any of the programmes
Reservation of seats: For SC and ST candidates, respectively 15% & 7.5% seats are reserved in each programme in all the IITs, IT-BHU, Varanasi and ISM, Dhanbad. Some candidates belonging to these categories who do not qualify in JEE-2010, may be offered admission to the Preparatory course of one-year duration provided (i) seats are available, (ii) candidates satisfy minimum norms, and (iii) candidates have not undergone the preparatory course earlier. Candidates successfully completing the preparatory course will be offered direct admission to the first year in the academic year 2011-12. For details, please refer to the information brochure or IIT websites
For OBC candidates belonging to non-creamy layer, 27% seats are reserved in each programme in all the IITs, IT-BHU, Varanasi and ISM, Dhanbad. Candidates belonging to this category are admitted on the basis of a relaxed criterion.
For candidates with physical disability (PD), including leprosy-cured candidates, and who are otherwise fit to pursue the course, 3% seats are reserved in each of the categories (viz. GE, OBC, SC and ST). Candidates in this category are also admitted under relaxed norms. In case the reserved seats are not filled, a limited number of PD candidates are admitted to a Preparatory course of one year duration on the basis of a further relaxation. Two seats in each institute are preferentially allotted to children of defence/paramilitary personnel killed or permanently disabled in action during war or peacetime operations (DS) and who qualify in the general category.
IIT JEE @ 2011
IIT JEE 2011 - Important Dates
Examination Schedule
Examination schedule: 10th April, 2011, (Sunday); Paper 1, 09.00-12.00 hrs; Paper 2, 14.00-17.00 hrs
Paper 1 and Paper 2 each will have separate sections in Chemistry, Physics and Mathematics
Both papers will be of objective type, designed to test comprehension, reasoning and analytical ability of candidates
Syllabus for this examination will be available on the website of all IITs
The candidate will have the option of submitting the application form either on-line or off-line
Important dates regarding application form and brochure
Online application process: Monday, 01st November, 2010 to Wednesday, 15th December, 2010
Sale of offline applications: Friday, 12th November, 2010 to Wednesday, 15th December, 2010
Last date for receipt of duly completed application forms (off-line or printed copy of on-line) at IITs:Monday, 20th December, 2010
Details regarding the application process will be published in leading national dailies and employment news/rozgar samachar on Saturday, 30th October, 2010
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Thursday, October 21, 2010
ece imp units
3-1 ECE
Managerial Economics and Financial Analysis (MEFA) - 1,2,4,5,7,8 Units
Computer Organization (CO) - 1,3,4,7,8 Units
Linear IC Applications - 1,2,3,4,7 Units
Digital IC Applications - 3,4,5,6,7 or 8 Units
Antennas and Wave Propagation - 3,4,5,6,7 Units
Digital Communications - 1,2,5,6,4Units
Managerial Economics and Financial Analysis (MEFA) - 1,2,4,5,7,8 Units
Computer Organization (CO) - 1,3,4,7,8 Units
Linear IC Applications - 1,2,3,4,7 Units
Digital IC Applications - 3,4,5,6,7 or 8 Units
Antennas and Wave Propagation - 3,4,5,6,7 Units
Digital Communications - 1,2,5,6,4Units
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