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1. If Rs. 782 be divided into three parts, proportional to : : , then the first part is:
A. Rs. 182
B. Rs. 190
C. Rs. 196
D. Rs. 204
Answer: Option D
Explanation:
Given ratio = 6 : 8 : 9.
1st part = Rs. 782 x 6= Rs. 204
2. If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?
A. 2: 5
B. 3 : 7
C. 5 : 3
D. 7 : 3
Answer: Option C
3. Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
A. 1/2
B. 2/5
C. 8/15
D. 9/20
Answer: Option D
Explanation:
Here, S = {1, 2, 3, 4, ...., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) = n(E) = 9 .
n(S) 20
Direction (for Q.No. 4):
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
4. How long will it take to empty the tank if both the inlet pipe A and the outlet pipe B are opened simultaneously?
I. A can fill the tank in 16 minutes.
II. B can empty the full tank in 8 minutes.
A. I alone sufficient while II alone not sufficient to answer
B. II alone sufficient while I alone not sufficient to answer
C. Either I or II alone sufficient to answer
D. Both I and II are not sufficient to answer
E. Both I and II are necessary to answer
Answer: Option E
Explanation:
I. A's 1 minute's filling work = 1/16
II. B's 1 minute's filling work = 1/8
(A + B)'s 1 minute's emptying work = 1/8 - 1/16 = 1/16
Tank will be emptied in 16 minutes.
Thus, both I and II are necessary to answer the question.
Correct answer is (E).
5. In how many different ways can the letters of the word 'OPTICAL' be arranged so that the vowels always come together?
A. 120
B. 720
C. 4320
D. 2160
E. None of these
Answer: Option B
Explanation:
The word 'OPTICAL' contains 7 different letters.
When the vowels OIA are always together, they can be supposed to form one letter.
Then, we have to arrange the letters PTCL (OIA).
Now, 5 letters can be arranged in 5! = 120 ways.
The vowels (OIA) can be arranged among themselves in 3! = 6 ways.
Required number of ways = (120 x 6) = 720.
6. Simran started a software business by investing Rs. 50,000. After six months, Nanda joined her with a capital of Rs. 80,000. After 3 years, they earned a profit of Rs. 24,500. What was Simran's share in the profit?
A. Rs. 9,423
B. Rs. 10,250
C. Rs. 12,500
D. Rs. 10,500
Answer: Option D
Explanation:
Simran : Nanda = (50000 x 36) : (80000 x 30) = 3 : 4.
Simran's share = Rs. 24500 x 3/7 = Rs. 10,500.
7. If selling price is doubled, the profit triples. Find the profit percent.
A. 66 (2/3)
B. 100
C.105(1/3)
D. 120
Answer: Option B
Explanation:
Let C.P. be Rs. x and S.P. be Rs. y.
Then, 3(y - x) = (2y - x) y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
8. Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:
A. 75
B. 81
C. 85
D. 89
Answer: Option C
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
First number = 551/29 = 19; Third number = 1073/29 = 37.
Required sum = (19 + 29 + 37) = 85.
9. Which of the following fractions is greater than 3/4 and less than 5/6 ?
A. 1/2
B. 2/3
C. 4/5
D. 9/10
Answer: Option C
Explanation:
3/4 = 0.75, 5 /6= 0.833, 1/2 = 0.5, 2/3 = 0.66, 4/5 = 0.8, 9/10 = 0.9.
Clearly, 0.8 lies between 0.75 and 0.833.
4/5 lies between 3/4 and 5/6 .
10. 34.95 + 240.016 + 23.98 = ?
A. 298.0946
B. 298.111
C. 298.946
D. 299.09
Answer: Option C
Explanation:
34.95
240.016
+ 23.98
--------
298.946
--------
11. If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?
A. 0.172
B. 1.72
C. 17.2
D. 172
Answer: Option C
Explanation:
| 29.94 | = | 299.4 |
| 1.45 | 14.5 |
| = | | 2994 | x | 1 | |
| 14.5 | 10 |
| = | 172 |
| 10 |
= 17.2
Direction (for Q.No. 12):
In each of the following questions, a question is asked and is followed by three statements. While answering the question, you may or may not require the data provided in all the statements. You have to read the question and the three statements and then decide whether the question can be answered with any one or two of the statements or all the three statements are required to answer the question. The answer number bearing the statements, which can be dispensed with, if any, while answering the question is your answer.
12. What is the compound interest earned at the end of 3 years?
I. Simple interest earned on that amount at the same rate and for the same period is Rs. 4500.
II. The rate of interest is 10 p.c.p.a.
III. Compound interest for 3 years is more than the simple interest for that period by Rs. 465.
A. I and II only
B. II and III only
C. I and III only
D. Either II or III only
E. Any two of the three
Answer: Option D
Explanation:
I. gives, S.I for 3 years = Rs. 4500.
II. gives, Rate = 10% p.a.
III. gives, (C.I.) - (S.I.) = Rs. 465.
Clearly, using I and III we get C.I. = Rs. (465 + 4500).
Thus, II is redundant.
Also, from I and II, we get sum = 100/10 x 4500/3 = 15000.
Now C.I. on Rs. 15000 at 10% p.a. for 3 years may be obtained.
Thus, III is redundant.
Either II or III is redundant.
13. The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:
A. 3500
B. 4000
C. 4050
D. 5000
Answer: Option B
Explanation:
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 x 2) = 10100 .... (i)
Q + R = (6250 x 2) = 12500 .... (ii)
P + R = (5200 x 2) = 10400 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)
Subtracting (ii) from (iv), we get P = 4000.
P's monthly income = Rs. 4000.
14. Rs. 20 is the true discount on Rs. 260 due after a certain time. What will be the true discount on the same sum due after half of the former time, the rate of interest being the same?
A.Rs. 10
B. Rs. 10.40
C. Rs. 15.20
D. Rs. 13
Answer: Option B
Explanation:
S.I. on Rs. (260 - 20) for a given time = Rs. 20.
S.I. on Rs. 240 for half the time = Rs. 10.
T.D. on Rs. 250 = Rs. 10.
T.D. on Rs. 260 = Rs. 10 x 260/250 = Rs. 10.40
Direction (for Q.No. 15):
Each of the questions given below consists of a statement and / or a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statement(s) is / are sufficient to answer the given question. Read the both statements and
Give answer (A) if the data in Statement I alone are sufficient to answer the question, while the data in Statement II alone are not sufficient to answer the question.
Give answer (B) if the data in Statement II alone are sufficient to answer the question, while the data in Statement I alone are not sufficient to answer the question.
Give answer (C) if the data either in Statement I or in Statement II alone are sufficient to answer the question.
Give answer (D) if the data even in both Statements I and II together are not sufficient to answer the question.
Give answer(E) if the data in both Statements I and II together are necessary to answer the question.
15. What is the two-digit number whose first digit is a and the second digit is b?. The number is greater than 9.
I. The number is multiple of 51.
II. The sum of the digits a and b is 6.
A. I alone sufficient while II alone not sufficient to answer
B. II alone sufficient while I alone not sufficient to answer
C. Either I or II alone sufficient to answer
D. Both I and II are not sufficient to answer
E. Both I and II are necessary to answer
Answer: Option A
Explanation:
From statement I:
A two digit number, greater than 9 and multiple of 51 should be 51 itself.
Because, 2 x 51 = 102 (3 digit number). Therefore, I alone sufficient to answer.
From statement II:
A two digit number, greater than 9 and sum of the digit is 6.
It can be 15, 24, 33, 42, 51. So we cannot determine the required answer from the statement II alone.
Thus, I alone give the answer while II alone not sufficient to answer.
Learn more problems on : Problems on Numbers
16. The curved surface area of a cylindrical pillar is 264 m2 and its volume is 924 m3. Find the ratio of its diameter to its height.
A. 3 : 7
B. 7 : 3
C. 6 : 7
D. 7 : 6
Answer: Option B
Explanation:
| | = | 924 | | | 924 | x 2 | | = 7 m. |
| 2 | 264 | 264 |
| And, 2 | | 264 x | 7 | x | 1 | x | 1 | | = 6m. |
| 22 | 2 | 7 |
| | 2r | = | 14 | = 7 : 3. |
| h | 6 |
17. A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
A. 23 days
B. 37 days
C. 37
D. 40 days
Answer: Option C
Explanation:
18. Today is Monday. After 61 days, it will be:
A. Wednesday
B. Saturday
C. Tuesday
D. Thursday
Answer: Option B
Explanation:
Each day of the week is repeated after 7 days.
So, after 63 days, it will be Monday.
After 61 days, it will be Saturday.
19. Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
A. 9
B. 11
C. 13
D. 15
Answer: Option D
Explanation:
Let the three integers be x, x + 2 and x + 4.
Then, 3x = 2(x + 4) + 3 x = 11.
Third integer = x + 4 = 15.
20. A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:
A. 588 apples
B. 600 apples
C. 672 apples
D. 700 apples
Answer: Option D
Explanation:
Suppose originally he had x apples.
Then, (100 - 40)% of x = 420.
60 x x/100 = 420
x = 420 x 100 /60 = 700.
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